Unit Conversions: mg, mcg, mL and Molar Units
One milligram (mg) equals 1,000 micrograms (µg or mcg). Both measure mass. Millilitres (mL) measure volume. To find the volume of solution containing a given mass of solute, you need its mass concentration. To convert mg/mL to molarity (mol/L), you need the solute’s molar mass in g/mol.
Mass and volume conversions
| Starting value | Equivalent value |
|---|---|
| 1 g | 1,000 mg |
| 1 mg | 1,000 µg (1,000 mcg) |
| 1 L | 1,000 mL |
| 1 mL | 1,000 µL |
| 1 mg/mL | 1 g/L = 1,000 µg/mL = 1 µg/µL |
For example, 0.75 mg = 750 micrograms. Converting back, 750 ÷ 1,000 = 0.75 mg. This reverse check catches a common thousand-fold error. [2]
How do you convert mg or mcg to mL?
For a solute in solution, divide its mass by its known mass concentration. If the concentration is in mg/mL and the mass is in mcg, first divide the mcg value by 1,000 to get mg. Then divide by the concentration. The units cancel as mg ÷ (mg/mL) = mL. A mass on its own leaves the volume undetermined. [3]
Molar units
Molarity is the amount of a specified solute, in moles, divided by the final solution volume in litres. Laboratory shorthand uses M for mol/L, mM for mmol/L and µM for µmol/L. Lower-case mm means millimetres. [3]
| Starting value | Equivalent value |
|---|---|
| 1 mol/L (1 M) | 1,000 mmol/L |
| 1 mmol/L (1 mM) | 1,000 µmol/L |
| 1 µmol/L (1 µM) | 1,000 nmol/L |
Convert mg/mL to molarity and back
Start with 1 mg/mL = 1 g/L. Divide the value in g/L by the solute’s molar mass in g/mol to get mol/L. In the reverse direction, multiplying mol/L by g/mol gives g/L, which has the same numerical value as mg/mL. [1] [3]
Use the molar mass for the chemical form represented by the mass measurement. If the mass is reported for a salt, check the salt form in the product specification before choosing the molar mass.
| Starting unit | Result unit | Numerical rule using molar mass in g/mol |
|---|---|---|
| mg/mL | mol/L (M) | Divide by the molar mass. |
| mol/L (M) | mg/mL | Multiply by the molar mass. |
| µg/mL | µmol/L (µM) | Multiply by 1,000, then divide by the molar mass. |
| mmol/L (mM) | µg/mL | Multiply by the molar mass. |
A fictional concentration example
Suppose 1.5 mL of final solution contains 3 mg of a single solute with a molar mass of 500 g/mol. These are teaching values for an invented material.
- Find the mass concentration. 3 mg ÷ 1.5 mL = 2 mg/mL = 2 g/L.
- Convert to molarity. (2 g/L) ÷ (500 g/mol) = 0.004 mol/L = 4 mmol/L (4 mM).
- Check in reverse. (0.004 mol/L) × (500 g/mol) = 2 g/L = 2 mg/mL.
For a second solution of the same 500 g/mol solute at 2 µg/mL, the numerical calculation is 2 × 1,000 ÷ 500 = 4, giving 4 µM. The original 2 mg/mL solution would be labelled 2,000 µg/mL.
The mass and molarity guide explains how to choose the mass basis for salts, complexes and individual constituents of a blend.
Avoid false precision
Use the final solution volume. The volume of solvent added can differ. A nominal fill or an HPLC peak-area percentage alone cannot establish the mass of the target solute. Keep the unrounded calculation in the laboratory record and report only the precision the inputs support.
The laboratory calculator supports mass concentration, optional molarity and aliquot arithmetic. It provides no syringe scale, international-unit conversion, per-subject quantity or administration schedule.
Keep the converted value and its input basis with the laboratory preparation record so another reader can reproduce the calculation.
Supporting checks
| Resource | Why open it |
|---|---|
| Net Peptide Content and Why It Is Not Purity | Distinguish peptide content from chromatographic purity. |
| Glossary | Look up a term and reach its fuller explanation. |
| Research Tools | Check which record and calculation resources are available. |
For guidance on laboratory quantities, preparation and record-keeping, browse the laboratory guides and research tools.
Sources and scope
- IUPAC Gold Book, “molar mass”Defines the mass per mole used to convert between g/L and mol/L.
- BIPM, SI prefixesLists the symbols and powers of ten for milli, micro and nano.
- NIST Guide to the SI, chapter 8Table 12 and sections 8.6.4–8.6.5 give the relationships between mass, amount of substance and mixture volume.